x^2+2=((x+2))/2

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Solution for x^2+2=((x+2))/2 equation: 


x in (-oo:+oo)

x^2+2 = (x+2)/2 // - (x+2)/2

x^2-((x+2)/2)+2 = 0

(-1*(x+2))/2+x^2+2 = 0

(-1*(x+2))/2+(2*x^2)/2+(2^2)/2 = 0

2*x^2-1*(x+2)+4 = 0

2*x^2-x-2+4 = 0

2*x^2-x+2 = 0

2*x^2-x+2 = 0

2*x^2-x+2 = 0

DELTA = (-1)^2-(2*2*4)

DELTA = -15

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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